The relationship between two numbers is described below, where x represents the first number and y represents the second number.The square of the first number is equal to the sum of the second number and 16. The difference of 4 times the second number and 1 is equal tothe first number multiplied by 7Select the equations that form the system that models this situation. Then, select the solution(s) of the system.

Answer:See below.Step-by-step explanation:x^2 = y + 164y - 1 = 7x  are the 2 equations. (answer)From the second equation 4y = 7x + 1 y = 7/4 x + 1/4Substituting in the first equation:7/4x + 1/4 + 16 = x^2x^2 - 7/4 x - 16 - 1/4 = 0x^2 - 7/4 x - 16 1/4 = 0Multiplying though by 44x^2 - 7x - 65 = 0Using the ac method to solve this  4 * -65 = -260 and we need  factors of this to add up to -7. -20 and 13 look good so we write:4x^2 - 20x + 13x - 65 = 0Fatcor by grouping:4x(x - 5) + 13(x - 5) = 0(4x + 13)(x - 5) = 0So the the roots are 5, -3.25To find the values of y we substitute these values of x into the second equation:x = 5:  4y - 1 = 7*542y = 36y = 9.x = -3.25:4y - 1 = 7*-3.254y =  (7 * -3.25) + 1y = -5.44.So the solutions are    (5, 9) and (-3.25, -5.44)  (Answer)